RMQSQ - Range Minimum Query
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You are given a list of N numbers and Q queries. Each query is specified by two numbers i and j; the answer to each query is the minimum number between the range [i, j] (inclusive).
Note: the query ranges are specified using 0-based indexing.
Input
The first line contains N, the number of integers in our list (N <= 100,000). The next line holds N numbers that are guaranteed to fit inside an integer. Following the list is a number Q (Q <= 10,000). The next Q lines each contain two numbers i and j which specify a query you must answer (0 <= i, j <= N-1).
Output
For each query, output the answer to that query on its own line in the order the queries were made.
Example
Input:
3
1 4 1
2
1 1
1 2
Output:
4
1
#####################################################CODE############################################
#include<iostream>
using namespace std;
int arr[1010000];
int tree[1010000];
int laz[10100000];
#define inf 999999999
int query(int node,int start,int end,int r1,int r2)
{
// cout<<start<<" "<<end<<endl;
if(laz[node])
{
tree[node]+=laz[node];
laz[2*node]+=laz[node];
laz[2*node+1]+=laz[node];
laz[node]=0;
}
if(start>end || r1>end || r2<start) return inf;
if(r1<=start && r2>=end)
{
return tree[node];
}
else
{
int q1=query(2*node,start,(start+end)/2,r1,r2);
int q2=query(2*node+1,((start+end)/2)+1,end,r1,r2);
return min(q1,q2);
}
}
void update(int node ,int start,int end,int r1,int r2,int val)
{
if(laz[node]!=0)
{
tree[node]+=laz[node];
laz[2*node+1]+=laz[node];
laz[2*node]+=laz[node];
laz[node]=0;
}
if(r1>end || r2<start || start>end) return ;
if(r1<=start && r2>=end)
{
tree[node]+=val;
if(start!=end)
{
laz[2*node]+=val;
laz[2*node+1]+=val;
}
return ;
}
update(2*node, start,(start+end)/2,r1,r2,val);
update(2*node+1, ((start+end)/2)+1,end,r1,r2,val);
tree[node]=min(tree[2*node],tree[2*node+1]);
}
void build(int node , int start,int end)
{
if(start==end) tree[node]=arr[start];
else if(start>end) return ;
else
{
build(2*node,start,(start+end)/2);
build(2*node+1,((start+end)/2)+1,end);
tree[node]=min(tree[2*node],tree[2*node+1]);
}
}
int main()
{
int n;
cin>>n;
for(int i=0;i<n;i++)
cin>>arr[i];
build(1,0,n-1);
// for(int i=0;i<20;i++) cout<<i<<" "<<tree[i]<<endl;
int q;
cin>>q;
while(q--)
{
int ip;
//cin>>ip;
/*if(ip==0)
{
int r1,r2,val;
cin>>r1>>r2>>val;
update(1,0,n-1,r1,r2,val);
}
else*/
{
int r1,r2;
cin>>r1>>r2;
int res= query(1,0,n-1,r1,r2);
cout<<res<<endl;
}
}
return 0;
}
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